How much downforce is created in F1 at what speeds?

I am doing a Research Report for Physics A2 and am trying to find out how much downforce is created by the F1 car at varying speeds.





I know that at max speed it has been said to be around 2.5 times the force of gravity.





Does anyone know figures for how much is created at say 50mph increments, in terms of how many times the force of gravity.





What sort of relationship is there between velocity and downforce, is it proportional, exponential etc.





Thank you to all|||12|||As the aerodynamic setup of an F1 car is dependent on the track, no definitive values can be given and add the fact that teams are highly protective about their designs. Set up for Monaco, an F1 car can generate a downforce equivalent to its own weight at about 200 kmph.





The link below gives a basic equation. However since the rules of aerodynamics are almost the same the force is proportional to the Lift Coefficient, density, angle of attack and area of the device and to the square of the velocity.|||Ok first down force is measured in Newton-meters not g's. G-force is measured in g's.





F1 teams are very secretive about how much down force their cars generate. I heard in an interview with an F1 designer that a modern F1 car generates enough down force at 100 MPH (I think it was 100 MPH that was quoted) that it could drive upside down. F1 cars with drivers weigh roughly 605 Kg. To drive upside down the car would have to generate at least 5933 Newton-meters in down force.|||remember: in an f1 car max g's are created while braking....or while decellaration...more speed/velocity while hitting the brakes,more is the downforce created...approx. 3-3.5g's(times the force of gravity)...