Two forces, F1, of magnitude 60 newtons (N) and F2 of magnitude 70 newtons, act on an object at angles of 40 degrees and 130 degrees (respectively) with the positive x-axis. Find the direction and magnitude of the resultant force, that is, find F1+F2. Round the direction and magnitude to two decimal places.
How do I do this? This is the only problem on my precalc study guide that I do not get. Please help!|||first you need to find the x and y components
F1x = cos 40 x 60N = 45.96
F1y = sin 40 x 60N = 38.57
F2x = cos 130 x 70N= -44.99
F2y = sin 130 x 70N = 53.62
Now you add the x and y components square each of them and find the square root
that will give you 92.20N that is the magnitude
Now for the direction you get the addition of the x and y components and find the tan^-1 y/x and that will give you the direction in degrees = 89.40 more or less
Hope it helps
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